15.04.2014 (21:57:56)
Janis B

:
RE:
Doktor- ""Why do you mix energy here? We are talking about average currents.""
Because few mails ago I wondered how energy conservation may work between input and output, if both currents are (p-p) equal but (rms) are hardly unequal.
However I begin to rethink what means half-wave input (what have here place) for driving igbt~s. Upper half-wave give full power, however bottom igbt works on just non-loaded inductivity reverting to start position. Cant it be the large current difference between them, and duplication of transported power if to use a full wave rectifier?? Existing is full wave by exit and half-wave by input.